Help me with my math homework

[Marth]

this shit is easy 115.5

[Marth]

or am i awnsering the wrong qeustion?

[C-Game]

i could figure it out but it would take forever cause i would go through every damn possiblity

yea steve yea
im stuck tooooooooooo

[C-Game]

this shit is easy 115.5

NO man
we r expectin 5 values

[C-Game]

i attend one of the top universities in the world... and all i have to say to you is...

GOOD LUCK because I can't figure this shit out!!

lol

hey this shld work except for the last cases

re check ur question coz im not sure
coz there are contradictions

instead of check the last two values
if its 119,120 then this sollution works

coz its 120 , 121 thr is a contradiction
anyway heres wat i did


a+b =110
a+c = 112
a+d =113
a+e =114

hmm so possibly there is
b+c = 115 ( possible ) coz combination factor

now addin up
a +b + a + c = 110 + 112
2a + b + c = 222
we know b+c is 115
and we use
2a = 222-115
2a=107
so a is =53.5

by substitutin a to the first couple of equatins u get
b=56.5
c=58.5
d=59.5
e=60.5


so ur answer is
53.5 , 56.5 , 58.5 , 59.5 , 60.5

[Rae]

i attend one of the top universities in the world... and all i have to say to you is...

GOOD LUCK because I can't figure this shit out!!

lol

hey this shld work except for the last cases

re check ur question coz im not sure
coz there are contradictions

instead of check the last two values
if its 119,120 then this sollution works

coz its 120 , 121 thr is a contradiction
anyway heres wat i did


a+b =110
a+c = 112
a+d =113
a+e =114

hmm so possibly there is
b+c = 115 ( possible ) coz combination factor

now addin up
a +b + a + c = 110 + 112
2a + b + c = 222
we know b+c is 115
and we use
2a = 222-115
2a=107
so a is =53.5

by substitutin a to the first couple of equatins u get
b=56.5
c=58.5
d=59.5
e=60.5


so ur answer is
53.5 , 56.5 , 58.5 , 59.5 , 60.5

wooooooooooooow ur smart!

i wish u were in my math class ... i would cheat off of u alot

[Hunneh_Buns]

Wow that's smart, but yeah only works with 119 and so on..

Date: 6/17/96 at 14:36:1
From: Doctor Alain
Subject: Re: The Haybaler Problem

Let the 5 bales be in increasing weight order and call their weights
B1, B2, B3, B4 and B5. There can't be 2 bales of the same weight or
else there would be pairs of bales with the same weight (if B1 = B2
then B1 + B3 = B2 + B3). The lightest pair is 110 kg so

(i) B1 + B2 = 110.

The second lightest pair is 112 kg so

(ii) B1 + B3 = 112.

The heaviest pair is 121 kg so

(iii) B4 + B5 = 121.

The second heaviest pair is 120 kg so

(iv) B3 + B5 = 120.

From (iv) and (ii) we get B5 = B1 + 8. If we put this back in (iii)
we get

(v) B1 + B4 = 113.

so the third lightest pair is bale 1 and bale 4. The fourth lightest pair
can be bails 1 and 5 OR bales 2 and 3.

So (vi.a) B1 + B5 = 114 OR (vi.b) B2 + B3 = 114.

Try each of these equations. One works out fine - the other doesn't.

-Doctor Alain, The Math Forum

I googled and that's what I got...someone explain.

[D@vid]

the weights are: 54,56,58,59,62

[Hunneh_Buns]

the weights are: 54,56,58,59,62

HOH SNAP! That works. Thank you.

May I ask how you got those numbers?

[D@vid]

just played with some of the numbers that the thing you got from google said.if you need to show the work, i don't know how to do that cuz i just moved the numbers around.

[Hunneh_Buns]

I don't need to show work, just wondering how you got numbers. But thanks a whole lot.

[Coccoa]

i attend one of the top universities in the world... and all i have to say to you is...

GOOD LUCK because I can't figure this shit out!!

lol

hey this shld work except for the last cases

re check ur question coz im not sure
coz there are contradictions

instead of check the last two values
if its 119,120 then this sollution works

coz its 120 , 121 thr is a contradiction
anyway heres wat i did


a+b =110
a+c = 112
a+d =113
a+e =114

hmm so possibly there is
b+c = 115 ( possible ) coz combination factor

now addin up
a +b + a + c = 110 + 112
2a + b + c = 222
we know b+c is 115
and we use
2a = 222-115
2a=107
so a is =53.5

by substitutin a to the first couple of equatins u get
b=56.5
c=58.5
d=59.5
e=60.5


so ur answer is
53.5 , 56.5 , 58.5 , 59.5 , 60.5

That has some logic in it.

Wait...how do we know b+c = 115 ??