Math :(

[Logann]

Write an Equaltion in slope intercept form of the line containing the given point and parallel to another line whose equation is given

1. y=2x + 1; (0,0)
2. y= -3x - 5; (1,1)

help me palease

[Nick419]

this is such an easy problem

[MuNxMuN]

i would help but i don't feel like going through my old notes

[D@vid]

1. y=2x + 1; (0,0)


slope of parallel line is same so, slope = 2
then plug in (0,0) into y -y1= m(x-x1)

u get y - 0 = 2 (x - 0) so then break that down and ur equation is

y = 2x




2.y = -3x - 5; (1,1)


slope = -3

y - 1 = -3 (x - 1)

break it down to
y = -3x + 3 +1
which gives u the answer as

y= -3x + 4

[xsibleyx03]

1. y=2x + 1; (0,0)


slope of parallel line is same so, slope = 2
then plug in (0,0) into y -y1= m(x-x1)

u get y - 0 = 2 (x - 0) so then break that down and ur equation is

y = 2x




2.y = -3x - 5; (1,1)


slope = -3

y - 1 = -3 (x - 1)

break it down to
y = -3x + 3 +1
which gives u the answer as

y= -3x + 4

my brain just blacked out whats that in english cheri?

[,-,'-{Bar}-',-,]

1. y=2x + 1; (0,0)


slope of parallel line is same so, slope = 2
then plug in (0,0) into y -y1= m(x-x1)

u get y - 0 = 2 (x - 0) so then break that down and ur equation is

y = 2x




2.y = -3x - 5; (1,1)


slope = -3

y - 1 = -3 (x - 1)

break it down to
y = -3x + 3 +1
which gives u the answer as

y= -3x + 4

thats the biggest lod of mumbo jumbo anyone has ever posted here

[D@vid]

1. y=2x + 1; (0,0)


slope of parallel line is same so, slope = 2
then plug in (0,0) into y -y1= m(x-x1)

u get y - 0 = 2 (x - 0) so then break that down and ur equation is

y = 2x




2.y = -3x - 5; (1,1)


slope = -3

y - 1 = -3 (x - 1)

break it down to
y = -3x + 3 +1
which gives u the answer as

y= -3x + 4

my brain just blacked out whats that in english cheri?

its easy. slope-intercept form is y=mx+b where m is the slope of the line and b is the y-intercept, the place where the line crosses the y axis. and the slope of a parallel line is the same for both lines that are parallel, so the slopes for the first lines is 2 and -3 for the second set, and u just plug that and the y-int they give u into the the equation y-y1=m(x-x1) where y1 and x1 are two given points, for the first one its (0,0) and (1,1) for the second. just get y on its own on one side and u have it in y-intercept form.


how hard is it ppl, this is like the easiest slope question ever. it gets a lot harder than this.

[xsibleyx03]

1. y=2x + 1; (0,0)


slope of parallel line is same so, slope = 2
then plug in (0,0) into y -y1= m(x-x1)

u get y - 0 = 2 (x - 0) so then break that down and ur equation is

y = 2x




2.y = -3x - 5; (1,1)


slope = -3

y - 1 = -3 (x - 1)

break it down to
y = -3x + 3 +1
which gives u the answer as

y= -3x + 4

my brain just blacked out whats that in english cheri?

its easy. slope-intercept form is y=mx+b where m is the slope of the line and b is the y-intercept, the place where the line crosses the y axis. and the slope of a parallel line is the same, so the slopes for the first lines is 2 and -3 for the second set, and u just plug that and the y-int they give u into the the equation y-y1=m(x-x1) where y1 and x1 are two given points, for the first one its (0,0) and (1,1) for the second. just get y on its own on one side and u have it in y-intercept form.

oh alright i see its slopes

[D@vid]

yeaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa

[4D]

That fuckin explanation was more confusion than your solution to the problem.

My hat goes off to you Mathmatheical people, looks like jargon to me, words always been my thing, letters and numbers don't mix!

[xsibleyx03]

:confusion:

That fuckin explanation was more confusion than your solution to the problem.

My hat goes off to you Mathmatheical people, looks like jargon to me, words always been my thing, letters and numbers don't mix!

algebra 1 for the 6th time *cause of semesters* and its the first time im passing it.....
im great with words

[Kez]

God i hate Maths, why did they make it compulsory?!

[D@vid]

:confusion:

That fuckin explanation was more confusion than your solution to the problem.

My hat goes off to you Mathmatheical people, looks like jargon to me, words always been my thing, letters and numbers don't mix!

algebra 1 for the 6th time *cause of semesters* and its the first time im passing it.....
im great with words

6th time


i have to start back with pre-calc in college after i went through calc in high school. thats the only reason i knew the answer cuz we just went over this. i never remember anything i learn.

[MuNxMuN]

1. y=2x + 1; (0,0)


slope of parallel line is same so, slope = 2
then plug in (0,0) into y -y1= m(x-x1)

u get y - 0 = 2 (x - 0) so then break that down and ur equation is

y = 2x




2.y = -3x - 5; (1,1)


slope = -3

y - 1 = -3 (x - 1)

break it down to
y = -3x + 3 +1
which gives u the answer as

y= -3x + 4

thats the biggest lod of mumbo jumbo anyone has ever posted here

you should see that chem explanation cubz posted

[xsibleyx03]

:confusion:

That fuckin explanation was more confusion than your solution to the problem.

My hat goes off to you Mathmatheical people, looks like jargon to me, words always been my thing, letters and numbers don't mix!

algebra 1 for the 6th time *cause of semesters* and its the first time im passing it.....
im great with words

haha duude im stupid


6th time


i have to start back with pre-calc in college after i went through calc in high school. thats the only reason i knew the answer cuz we just went over this. i never remember anything i learn.